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Mathematics 16 Online
OpenStudy (anonymous):

In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA−→ and BC−→. Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.

OpenStudy (anonymous):

OpenStudy (mertsj):

The construction is of the angle bisector so angle ABP is 32 and angle ABC is 64

OpenStudy (anonymous):

Okay, but the second part?..

OpenStudy (mertsj):

What is the second part? I don't see a second part.

OpenStudy (anonymous):

This.

OpenStudy (mertsj):

When someone tries to help you, would it be too much trouble for you to read what they have written?

OpenStudy (anonymous):

I just do not understand it...

OpenStudy (mertsj):

so angle ABP is 32 and angle ABC is 64

OpenStudy (anonymous):

OH.

OpenStudy (anonymous):

I did not realize that is what you were saying. I feel very stupid. I apologize.

OpenStudy (mertsj):

np

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