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In the diagram, points D and E are marked by drawing arcs of equal size centered at B such that the arcs intersect BA−→ and BC−→. Then, intersecting arcs of equal size are drawn centered at points D and E. Point P is located at the intersection of these arcs.
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The construction is of the angle bisector so angle ABP is 32 and angle ABC is 64
Okay, but the second part?..
What is the second part? I don't see a second part.
This.
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When someone tries to help you, would it be too much trouble for you to read what they have written?
I just do not understand it...
so angle ABP is 32 and angle ABC is 64
OH.
I did not realize that is what you were saying. I feel very stupid. I apologize.
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np
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