Question

n ΔABC, BC = a = 16, AC = b = 10, and m∠C = 22°. Which equation can you use to find the value of c = AB?

Answer 1

can i see the answer choices?

Answer 2

there are none, you have to type your answer

Answer 3

here is the picture! http://cdn.ple.platoweb.com/PCAP-ASSETS-PROD/f0e6b9bb6f804e60999f40d25bb55b7c

Answer 4

here you can apply the theorem of Carnot, namely:
\[\Large \begin{gathered}
{c^2} = {a^2} + {b^2} - 2ab\cos \left( {22} \right) = \hfill \\
\hfill \\
= {16^2} + {10^2} - 2 \times 16 \times 10\cos \left( {22} \right) = ... \hfill \\
\end{gathered} \]

Answer 5

i dont get it?

Answer 6

ok! Now you have to compute this:
\[\Large \sqrt {59.30} = ...?\]

Answer 7

what do you get?

Answer 8

none of it, i've been working on this for 3 days (not this particular question) and it only gets more and more confusing

Answer 9

we have:
\[\large \begin{gathered}
{c^2} = {a^2} + {b^2} - 2ab\cos \left( {22} \right) = \hfill \\
\hfill \\
= {16^2} + {10^2} - 2 \times 16 \times 10\cos \left( {22} \right) = \sqrt {59.30} \cong 7.7 \hfill \\
\end{gathered} \]

Answer 10

am I right?

Answer 11

yes

Answer 12

to see it written out, makes it somewhat easier but when its a different problem and i try and do it myself, i get it wrong

Answer 13

that is a simple application of the Theorem of Carnot

Answer 14

thank you

Answer 15

:)