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How would you complete the square on the left side of this equation? x^2-6x=15 A. Add 6 to both sides of the equation. B. Subtract 6 from both sides of the equation. C. Add 9 to both sides of the equation. D. Subtract 9 from both sides of the equation.
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you need to convert the left side to (x - 3)^2 if you expand that you'll find that the last number is what you want
HI!!
two steps only what is half of 6?
3
right and what is \(3^2\)
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9
that is your answer , 9
D
because if \[x^2-6x=15\] then adding 9 gives \[x^2-6x+9=15+9\\ (x-3)^2=24\]\]
no dear never subtract when you are completing the square you always ADD
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