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The area of a trapezoid is 69 inches squared. Its bases have lengths 9 inches and 14 inches. Find the height of the trapezoid.
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\[area=\frac{ 14+9 }{ 2 }*h=69\] find h.
The area of a trapezoid is given by the formula \[A=\frac{ \left( b_{1}+b_{2} \right)h }{ 2}\] where \[A\] is the area, \[b_{1},b_{2}\] are the bases and \[h\] is the height. Therefore, \[69=\frac{ \left( 9+14 \right)h }{ 2 }\] and so \[h=6\] inches.
How did you find the Height though?
What is the formula for the area of a trapezoid?
\[A=1/2h(b1+b2)\]
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@valiant1 We have \[69=\frac{ \left( 9+14 \right)h }{ 2 }\] which implies \[69=\frac{ 23h }{ 2 }\] so \[h=\frac{ 2 }{ 23 }\times69 =6\] Hope this answers your question.
Aww ok. and one more question how did you know to flip it?
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