Question

Two equations are shown:
• Equation 1:
3/4(x−12)=12
•Equation 2:
3/4y−12=12

Solve each equation. Then, enter a number in each box to make this statement true.

The value of x is:

The value of y is:

Answer 1

\[\dfrac34(x-12)=12\]

We need to isolate x. Any idea what to do with \(\dfrac34\)?

Answer 2

convert it to a decimal?

Answer 3

Sure. Then we have \(.75(x-12) = 12\)

We still need to get rid of .75

Answer 4

Maybe do something to both sides to cancel .75 out?

Answer 5

subtract .75 from .75 and 12?

Answer 6

I would go with dividing.

Answer 7

\(\dfrac{.75(x-12)}{.75} = \dfrac{12}{.75}\)


\(\dfrac{\cancel{.75}(x-12)}{\cancel{.75}} = \dfrac{12}{.75}\)

\(x-12 = \dfrac{12}{.75}\)

Answer 8

okk

Answer 9

Do you understand what is going on?

Answer 10

yes so 12 divided by .75 is 16?

Answer 11

so then 12/.75 is equal; to 9,

Answer 12

okk so x=28? 28-12=16 witch is 16=16? right

Answer 13

yes that right :)

Answer 14

yay thank u guys!!!!! :-)

Answer 15

now equation 2 I need help also

Answer 16

do I do the same thing as I did the first time?

Answer 17

no its then 3/4Y-12 = 12 you add 12 to both sides and its 3/4Y = 24 you divide btoh sides by 3/4 and its Y = 32

Answer 18

its a lot to chew so if you get stuck ill help you with each part

Answer 19

yea I'm a little confused can u explain please