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You have a 3-card deck containing a king, a queen, and a jack. You draw a random card, put it back, and draw a second random card. What is the probability that you draw exactly 1 jack?
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On each draw, the probability of drawing a Jack is 1/3 and the probability of not drawing a Jack is 2/3. The events 'draw a Jack' and 'not draw a Jack' are independent. There are two ways to draw one Jack, on the first draw or on the second draw. Therefore the required probability is: \[\large \frac{2\times1\times2}{3\times3}=you\ can\ calculate\]
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