Question

How would I solve this problem? I'll post it in the comments.

Answer 1

have u heard about triplets

Answer 2

I'm not sure. I don't think so.

Answer 3

if i was at ur place i would have checked with the options

\(x^2+y^2=28\) which ever fits

Answer 4

it should be this


\(\large \color{black}{\begin{align}&x^2+y^2=28^2\hspace{.33em}\\~\\

\end{align}}\)

Answer 5

this should be helpful

\(\large \color{black}{\begin{align}&x^2-16^2=y^2-12^2\hspace{.33em}\\~\\
& x^2+y^2=28^2

\end{align}}\)

Answer 6

Wait, how did you get that?

Answer 7

\(\large \color{black}{\begin{align}&x^2=h^2+16^2\hspace{.33em}\\~\\
&y^2=h^2+12^2\hspace{.33em}\\~\\

\end{align}}\)