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Can someone check this?
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Here is what I did: http://www.wolframalpha.com/input/?i=tell+me+the+arc+length+of+y%3D6x%2Bsin+x+from+x%3D0+to+6pi
But no 37...
@ganeshie8 @phi @zepdrix
multiply the stuff under the radical from the wolfram integral
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ok. Give me a sec
its not b.) i think
dy/dx = 6 + cos x arc lenght = integral √(1 + (dy/dx)²) you need to simplify 1 + (6 + cos² x)²
Ohhh. So it must be A then.
yeah it looks so
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It looks like choices A and C are the same ?
No, the limits are different :)
oh, good
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