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Mathematics 17 Online
OpenStudy (anonymous):

Help

OpenStudy (anonymous):

OpenStudy (anonymous):

Just tell me how to solve it (formula, etc.)

ganeshie8 (ganeshie8):

is it given that PS is perpendicular to QR ?

OpenStudy (amoodarya):

is PS pependicular to Qr ?

OpenStudy (anonymous):

nope nothing else is given

OpenStudy (amoodarya):

if there is no condition more ,this is not solvable ! but if ps perpendicular to qr first \[qs^2+9^2=15^2\\qs=12\]

OpenStudy (anonymous):

pythagoras theorem? right?

OpenStudy (amoodarya):

then use sin60 to find pr and use cos 60 to find sr \[\sin60=\frac{ \sqrt{3} }{ 2 }=\frac{ 12 }{ pr}\\cos 60 =\frac{ 1 }{ 2 }=\frac{ sr }{ pr}\] from the first find pr put in second , and find sr

OpenStudy (amoodarya):

pythagoras ,yes

OpenStudy (anonymous):

Parameter is 44.79?

OpenStudy (anonymous):

@UsukiDoll can you check the answer?

OpenStudy (usukidoll):

I was afk :/

OpenStudy (anonymous):

Its ok

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