I had this same question on a test and I guessed and got it right!
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OpenStudy (phi):
It may not be obvious but both angle C and angle BDR have the *same intercepted arc*
OpenStudy (anonymous):
Oh
OpenStudy (anonymous):
Thanks guys!
OpenStudy (anonymous):
Appreciate it!
OpenStudy (anonymous):
np
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OpenStudy (phi):
If inscribed angles have the same arc, then they are both 1/2 of that arc.
they both are equal to the same value.
OpenStudy (anonymous):
Yeah
OpenStudy (phi):
so if C=63 what is angle BDR ?
OpenStudy (anonymous):
But sometimes it gets a little confusing because looks like it's not actually intercepting the arch and is just running straight through. That's usually what stumps me.
OpenStudy (phi):
Yes, the tangent is a special case. But we (or somebody) can prove the angle BDR equals 1/2 of the arc from B to D the short way (through A)
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OpenStudy (phi):
so if C=63 what is angle BDR ?
OpenStudy (anonymous):
90?
OpenStudy (anonymous):
Oh it should actually be 63 right?And not 90?
OpenStudy (phi):
I guess you are missing the point.
Do you agree that angle C is 1/2 of its intercepted arc (which is from B to D the short way)
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