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Geometry 11 Online
OpenStudy (anonymous):

*Medal Will Be Awarded!* Given: Line DR tangent to Circle O. If m Ancle C = 63°, then m Angle BDR = a) 63 b) 90 c) 126

OpenStudy (anonymous):

B

OpenStudy (anonymous):

How so?

OpenStudy (anonymous):

Can You Show Me?

OpenStudy (anonymous):

I had this same question on a test and I guessed and got it right!

OpenStudy (phi):

It may not be obvious but both angle C and angle BDR have the *same intercepted arc*

OpenStudy (anonymous):

Oh

OpenStudy (anonymous):

Thanks guys!

OpenStudy (anonymous):

Appreciate it!

OpenStudy (anonymous):

np

OpenStudy (phi):

If inscribed angles have the same arc, then they are both 1/2 of that arc. they both are equal to the same value.

OpenStudy (anonymous):

Yeah

OpenStudy (phi):

so if C=63 what is angle BDR ?

OpenStudy (anonymous):

But sometimes it gets a little confusing because looks like it's not actually intercepting the arch and is just running straight through. That's usually what stumps me.

OpenStudy (phi):

Yes, the tangent is a special case. But we (or somebody) can prove the angle BDR equals 1/2 of the arc from B to D the short way (through A)

OpenStudy (phi):

so if C=63 what is angle BDR ?

OpenStudy (anonymous):

90?

OpenStudy (anonymous):

Oh it should actually be 63 right?And not 90?

OpenStudy (phi):

I guess you are missing the point. Do you agree that angle C is 1/2 of its intercepted arc (which is from B to D the short way) |dw:1435584558053:dw|

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