*Medal Will Be Awarded!* Given: Line DR tangent to Circle O. If m Ancle C = 63°, then m Angle BDR = a) 63 b) 90 c) 126
B
How so?
Can You Show Me?
I had this same question on a test and I guessed and got it right!
It may not be obvious but both angle C and angle BDR have the *same intercepted arc*
Oh
Thanks guys!
Appreciate it!
np
If inscribed angles have the same arc, then they are both 1/2 of that arc. they both are equal to the same value.
Yeah
so if C=63 what is angle BDR ?
But sometimes it gets a little confusing because looks like it's not actually intercepting the arch and is just running straight through. That's usually what stumps me.
Yes, the tangent is a special case. But we (or somebody) can prove the angle BDR equals 1/2 of the arc from B to D the short way (through A)
so if C=63 what is angle BDR ?
90?
Oh it should actually be 63 right?And not 90?
I guess you are missing the point. Do you agree that angle C is 1/2 of its intercepted arc (which is from B to D the short way) |dw:1435584558053:dw|
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