Question

Solve this problem on paper using all four steps.

Find four consecutive integers whose sum is 114.

The integers are , , , and .

Answer 1

do 114/4=28.5 then pick 2 numbers greater than and 2 less than in a row 27+28+29+30=114

Answer 2

let suppose n is the interger
four consecutive integers are
n, n+1,n+2,n+3
solution :-

n+ n+1+n+2+n+3=114
4n +6=114
4n =114-6
4n = 108
n = 108 /4
n= 27

so four consecutive integers will be
27, 28, 29, 30

Answer

Answer 3

@jjmack2 dont forget to medal and fan those who help u

Answer 4

hint:
your problem can be modeled by the subsequent equation:
\[\Large n + \left( {n + 1} \right) + \left( {n + 2} \right) + \left( {n + 3} \right) = 114\]

Answer 5

where n is an integer number

Answer 6

please, solve that equation for n