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Mathematics 8 Online
OpenStudy (mckenzieandjesus):

is tangent to circle O at B. What is the length of the radius r? Round to the nearest tenth. 15.4 6.1 1.7 2.9

OpenStudy (mckenzieandjesus):

OpenStudy (mckenzieandjesus):

@jim_thompson5910

OpenStudy (mckenzieandjesus):

@Hero

hero (hero):

@mckenzieandjesus, What kind of triangle is ABO?

OpenStudy (mckenzieandjesus):

acute?

OpenStudy (mckenzieandjesus):

wait a right?

hero (hero):

If segment AB is tangent to circle O at point B, what does that say about segments AB and OB? Yes, it is a right triangle. Which means what?

OpenStudy (mckenzieandjesus):

its 90 degrees

OpenStudy (mckenzieandjesus):

AB and OB are equal?

hero (hero):

Well, you're given two sides of the right triangle and need to find the length of the third side. What rule do we use for this situation?

OpenStudy (mckenzieandjesus):

Pythagorean theorem?

OpenStudy (mckenzieandjesus):

a2 + b2 = c2?

hero (hero):

Exactly. \(a^2 + b^2 = c^2\)

OpenStudy (mckenzieandjesus):

\[10 ^{2}+11.7 ^{2} = 236 \frac{ 89 }{ 100 }\]

OpenStudy (mckenzieandjesus):

236 89/100^2 = 56116.8721

hero (hero):

Actually, you have to find the correct "a", "b" and "c" when using the pythagorean theorem.

OpenStudy (mckenzieandjesus):

how do i do that?

hero (hero):

"a" and "b" are always the "legs" of the right triangle. "c" is always the hypotenuse. Sometimes, they give you "a" and "c", but not "b".

OpenStudy (mckenzieandjesus):

10+1.7= 11 7/10

OpenStudy (mckenzieandjesus):

can u help with this one? Point P is the center of two concentric circles. PQ = 10.5 and PS = 20.9. RS is tangent to the smaller circle and a chord of the larger circle. What is length of RS to the nearest tenth? 36.1 41.4 31.4 41.8

hero (hero):

Your work for the problem you originally posted is not correct.

OpenStudy (mckenzieandjesus):

this one?

hero (hero):

ya, this one.

OpenStudy (mckenzieandjesus):

i did it wrong? how?

OpenStudy (mckenzieandjesus):

10^2+1.7^2= 102 89/100?

OpenStudy (mckenzieandjesus):

@Hero

hero (hero):

I thought you already learned about right triangles. I'm going to say it again. Sometimes, you're given "c" instead of "b", which means, if you have something like a = 3 c = 5 then you have to solve for b: a^2 + b^2 = c^2 3^2 + b^2 = 5^2 b^2 = 5^2 - 3^2 b^2 = 25 - 9 b^2 = 16 b = 4

OpenStudy (mckenzieandjesus):

i got 132.89 how do i make it smaller?

OpenStudy (mckenzieandjesus):

11.5?

OpenStudy (mckenzieandjesus):

10^2+11.5^2= 232 1/4

OpenStudy (mckenzieandjesus):

232.25

OpenStudy (mckenzieandjesus):

still lost.. @Hero

OpenStudy (mckenzieandjesus):

@pooja195

hero (hero):

Yes, I can tell. I think I know something that might be useful for you. Try ixl.com

OpenStudy (mckenzieandjesus):

ok..

OpenStudy (mckenzieandjesus):

@jim_thompson5910

OpenStudy (mckenzieandjesus):

i did it in the steps u showed me @Hero

hero (hero):

In this case, a = r b = 10 c = 11.7 So \(a^2 + b^2 = c^2\) becomes: \(r^2 + 10^2 = 11.7^2\) You subtract 10^2 from both sides: \(r^2 = 11.7^2 - 10^2\) Then square root both sides to get \(r = \sqrt{11.7^2 - 10^2} \)

hero (hero):

You'll have to finish simplifying \(r\) on your own. I'm not going to do that for you. Just let me know what you get. I'll say whether or not it's right or wrong.

OpenStudy (mckenzieandjesus):

square root 11.7^2-10^2 = 6.073713856?

OpenStudy (mckenzieandjesus):

6.1?

hero (hero):

Correct.

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