Tabitha is trying to find the equation of a line perpendicular to y = 1 over 2x − 5 in slope-intercept form that passes through the point (2, −7). Which of the following equations will she use?
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OpenStudy (anonymous):
a) y − (−7) = 1 over 2(x − 2)
b) y − 2 = 1 over 2(x − (−7))
c) y − (−7) = −2(x − 2)
d) y − 2 = −2(x − (−7))
OpenStudy (anonymous):
@satellite73
OpenStudy (anonymous):
you been at this one for a while huh?
OpenStudy (anonymous):
yes! can't seem to figure it out :(
OpenStudy (anonymous):
ok lets go slow (but not that slow)
the slope of
\[y=\color{red}{\frac{1}{2}}x-5\] is ?
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OpenStudy (anonymous):
hint: it is red
OpenStudy (anonymous):
1/2
OpenStudy (anonymous):
right
and the perpendicular line with have a slope that is the "negative reciprocal" i.e. flip it and change the sign
OpenStudy (anonymous):
2/1?
OpenStudy (anonymous):
-2/1*
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OpenStudy (anonymous):
right, which, on planet earth, we usually just call \(-2\)
OpenStudy (anonymous):
haha right
OpenStudy (anonymous):
now we got the slope
the point is \((2,-7)\) and they want you to plug all this in to the "point - slope" formula
\[y-y_1=m(x-x_1)\]
OpenStudy (anonymous):
where you see \(y_1\) put \(-7\)
where you see \(m\) put \(-2\) and
where you see \(x_1\) put \(2\)
OpenStudy (anonymous):
so would it be c?
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