Mathematics
12 Online
OpenStudy (anonymous):
Solve the system of equations
5x-y=3 and -10x+2y=-6
Answers:
A; 0.-3
B: -3.0
C: 3,12
D: no solution
E: infinitely many solutions
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
isolate y in the first equation
OpenStudy (anonymous):
can you do that?
OpenStudy (anonymous):
I don't think so... Am I rewriting the first equation?
OpenStudy (anonymous):
ya you want y by itself
OpenStudy (anonymous):
first add y to both sides
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
5x=3+y
OpenStudy (anonymous):
then subtract 3 from both sides
OpenStudy (anonymous):
y=5x-3
OpenStudy (anonymous):
now plug in (5x-3) for y in the second equation
OpenStudy (anonymous):
-10x+2(5x-3)=-6
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
now try and solve for x
OpenStudy (anonymous):
-10x+4=-6?
OpenStudy (anonymous):
no, foil out 2(5x-3)
OpenStudy (anonymous):
Wouldn't I have to do 2 times 5 then 2 times 3
OpenStudy (anonymous):
2 times 5 plus 2 times -3
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
*2 times 5x
OpenStudy (anonymous):
2 times 5x= 10x
2 times =3= -6
OpenStudy (anonymous):
thats right, so we have
-10x + 10x - 6 = -6
OpenStudy (anonymous):
simplify that
OpenStudy (anonymous):
Simplify? Like break it down again
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
you want to get x by itself to solve it
OpenStudy (anonymous):
Do you minus one of them on both sides
OpenStudy (anonymous):
lets just look at the x's.
what is -10x + 10x?
OpenStudy (anonymous):
0..
OpenStudy (anonymous):
that's right
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Yayy
OpenStudy (anonymous):
so what should be your answer?
OpenStudy (anonymous):
0,-3?
OpenStudy (anonymous):
no, how did you get -3?
anyways, since the x's cancel out there can't be a solution to this system of eqaution
OpenStudy (anonymous):
Ah okay >< sorry, thanks for your help!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
no problem