Question

I need someone to explain this to me
Let u = <-5, 1>, v = <7, -4>. Find 9u - 6v.

Answer 1

\(\bf a <b,c>~ =~ <ab,ac>\)

Answer 2

I don't understand?

Answer 3

@TheSmartOne

Answer 4

\(\bf y=~<a,b>\)
\(\bf z=~<c,d>\)

\(\bf y-z =\)

\(\sf <a,b> - <c,d>~= ~<a,b> -<c,d>~=~<a-c,~b-d>\)

Answer 5

okay im even more confused

Answer 6

\(\bf y=~<a,b>\)
\(\bf z=~<c,d>\)

\(\bf y-z =\)

\(\sf <a,b> - <c,d>~=~<a-c,~b-d>\)

Oops, fixed the redundant error...

Answer 7

https://www.mathsisfun.com/algebra/vectors.html

Review the topic :p

Answer 8

could you possibly plug in the numbers for the Y & Z?

Answer 9

Yes i need an explanation, not symbols

Answer 10

\(\bf u= ~<-5,1>\)

\(\bf 9u = 9<-5,1>~= <9\times (-5) , 9\times 1>\)

Answer 11

That's unfortunate, because we can't solve this without the vector symbol :p

Answer 12

so what is

\(\sf 9\times (-5) =?\)

and

\(\sf 9\times1 =?\)

Answer 13

-45 & 9

Answer 14

correct, so now we have

\(\bf 9u =~<-45,9>\)