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OpenStudy (anonymous):
What is the vertex of this quadratic function?
f(x) = 2x2 + 4x − 5
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OpenStudy (danjs):
which math class are you taking
OpenStudy (anonymous):
math2
OpenStudy (danjs):
algebra
OpenStudy (anonymous):
oh yeah
OpenStudy (danjs):
so you need to turn y = ax^2 + bx + c into
y = a*(x-h)^2 + k
the vertex form
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OpenStudy (danjs):
the vertex in that is the point (h,k)
OpenStudy (anonymous):
i dont get it
OpenStudy (jenma):
U know how to find the axis of symmetry?
OpenStudy (danjs):
you can play with that , or simply remember,
the x coordinate of the vertex of y = ax^2 + bx + c is
x = -b / (2*a)
OpenStudy (danjs):
as jenma said , or also the axis of symm
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OpenStudy (danjs):
then use that x value , and calculate what y is,, the point (x,y) is the vertex
OpenStudy (danjs):
gl
OpenStudy (anonymous):
ty
OpenStudy (jenma):
Yes @DanJS . Find the axis of symmetry first and then when u find the answer u would do the substitute of the equation and u will find the vertex...
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