What is the vertex of this quadratic function? f(x) = 2x2 + 4x − 5
which math class are you taking
math2
algebra
oh yeah
so you need to turn y = ax^2 + bx + c into y = a*(x-h)^2 + k the vertex form
the vertex in that is the point (h,k)
i dont get it
U know how to find the axis of symmetry?
you can play with that , or simply remember, the x coordinate of the vertex of y = ax^2 + bx + c is x = -b / (2*a)
as jenma said , or also the axis of symm
then use that x value , and calculate what y is,, the point (x,y) is the vertex
here is an example i just found... http://hotmath.com/hotmath_help/topics/vertex-of-a-parabola.html
gl
ty
Yes @DanJS . Find the axis of symmetry first and then when u find the answer u would do the substitute of the equation and u will find the vertex...
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