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OpenStudy (anonymous):
Can someone help me with this:
Find all solutions in the interval [0, 2pi) .
7 tan^3x - 21 tan x = 0
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OpenStudy (danjs):
try factoring tan(x) out first, so tan(x) = 0, recall identities to replace tan^2 and tan by sin and cos maybe
OpenStudy (danjs):
those probs just play around till you get something in terms of sin and cos using identities and algebra
OpenStudy (danjs):
\[7\tan(x)[\tan^2(x) -3]=0\]
\[7\tan(x)[\frac{ \sin^2(x) }{ \cos^2(x) } -3]=0\]
OpenStudy (anonymous):
Here
OpenStudy (anonymous):
On the very left its pie.k and not pie
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OpenStudy (anonymous):
@DanJS what are you doing ? :s
OpenStudy (anonymous):
I mean very right* on the bottom +pie.k
OpenStudy (danjs):
lol idk, you have it right,
use the unit circle, tan(x)=y/x, remember symmetries if needed for multiple answers over the domain
OpenStudy (anonymous):
Thats better
OpenStudy (danjs):
looks right
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OpenStudy (anonymous):
Oh and since its limited between ]0,2pie[
Then you write my answer and add for k=0,1,2
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