Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (sloppycanada):

Triangle ABC is congruent to triangle XYZ. Angel A measures 50 degrees. Angle B measures (2x+40) and angle Y (4x+8). Find the value of x. How do I set this up proportionally?

OpenStudy (anonymous):

|dw:1435807242985:dw| The vertices correspond. a-x b-y c-z

OpenStudy (anonymous):

then you can set angle b = y and solve for x

OpenStudy (sloppycanada):

x = 8? I can't believe I did not see that. It looks so simple now that you've written it...

OpenStudy (anonymous):

I've been there many a-time :p

OpenStudy (sloppycanada):

Sorry x =16.

OpenStudy (anonymous):

2x=32 x=16 yeah

OpenStudy (sloppycanada):

ABC is congruent to XYZ. A = 50 B = 2x+40, Z = 4x + 8

OpenStudy (anonymous):

you can make C = z then you know that all interior angle triangle angles add up to 180

OpenStudy (sloppycanada):

|dw:1435807481419:dw| Like this?

OpenStudy (sloppycanada):

But I don't have the value of "C"

OpenStudy (anonymous):

c is z remember the congruence statement abc=xyz a=x b=y c=z

OpenStudy (anonymous):

|dw:1435807584943:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!