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Triangle ABC is congruent to triangle XYZ. Angel A measures 50 degrees. Angle B measures (2x+40) and angle Y (4x+8). Find the value of x. How do I set this up proportionally?
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|dw:1435807242985:dw| The vertices correspond. a-x b-y c-z
then you can set angle b = y and solve for x
x = 8? I can't believe I did not see that. It looks so simple now that you've written it...
I've been there many a-time :p
Sorry x =16.
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2x=32 x=16 yeah
ABC is congruent to XYZ. A = 50 B = 2x+40, Z = 4x + 8
you can make C = z then you know that all interior angle triangle angles add up to 180
|dw:1435807481419:dw| Like this?
But I don't have the value of "C"
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c is z remember the congruence statement abc=xyz a=x b=y c=z
|dw:1435807584943:dw|
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