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Mathematics 27 Online
OpenStudy (anonymous):

Belinda wants to invest $1000. The table below shows the value of her investment under two different options for three different years: Number of years 1 2 3 Option 1 (amount in dollars) 1100 1210 1331 Option 2 (amount in dollars) 1100 1200 1300 Part A: What type of function, linear or exponential, can be used to describe the value of the investment after a fixed number of years using option 1 and option 2? Explain your answer. (2 points) Part B: Write one function for each option to describe the value of the investment f(n), in dollars, after n years. (4 points)

OpenStudy (anonymous):

do you know how to do it

OpenStudy (anonymous):

@misssunshinexxoxo

OpenStudy (anonymous):

@amoodarya

OpenStudy (anonymous):

@welshfella

OpenStudy (anonymous):

can you help me

OpenStudy (welshfella):

i gotta go sorry Option 2 is linear

OpenStudy (anonymous):

ok thanks

OpenStudy (anonymous):

can some one help me

OpenStudy (anonymous):

@Tinkerbell2001

OpenStudy (anonymous):

do you know how to do this @Tinkerbell2001

OpenStudy (anonymous):

option 1 is exponential

OpenStudy (anonymous):

if you graph it the line will curve up slightly

OpenStudy (anonymous):

ok so what would the functions look like

OpenStudy (anonymous):

|dw:1435949012369:dw|

OpenStudy (anonymous):

that's what option 1 would look like

OpenStudy (anonymous):

|dw:1435949041634:dw|

OpenStudy (anonymous):

thats what 2 would look like

OpenStudy (anonymous):

ok cool but its says for put together a function and write it out do i just put those graphs as it

OpenStudy (anonymous):

you need to find the equation for the lines

OpenStudy (anonymous):

idk that part thats what i was trying to ask you about

OpenStudy (anonymous):

ok lets find the equation for option 2 first

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

it will be in the form y=mx+b

OpenStudy (anonymous):

are you familiar with this?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok, try and solve it

OpenStudy (anonymous):

so it will look like y=1000x+1100

OpenStudy (anonymous):

yo @10115658

OpenStudy (anonymous):

sorry i was afk

OpenStudy (anonymous):

that isn't correct

OpenStudy (anonymous):

how do you find the slope?

OpenStudy (anonymous):

pick 2 points

OpenStudy (anonymous):

lets pick (1,1100) and (2,1200)

OpenStudy (anonymous):

slope is y2-y1/x2-x1

OpenStudy (anonymous):

(1200-1100)/(2-1)

OpenStudy (anonymous):

the slope is 100

OpenStudy (anonymous):

now lets find the y-intercept

OpenStudy (anonymous):

y=100x+b

OpenStudy (anonymous):

plug in one of the points for x and y

OpenStudy (anonymous):

1100=100+b

OpenStudy (anonymous):

now solve for b

OpenStudy (anonymous):

b=1000

OpenStudy (anonymous):

ok, so now we have our equation y=100x+1000

OpenStudy (anonymous):

now they want it in terms of f(n) and n so we rewrite it as f(n)=100n+1000

OpenStudy (anonymous):

that's the answer for option 2

OpenStudy (anonymous):

does that make sense?

OpenStudy (anonymous):

you there?

OpenStudy (anonymous):

yeah im here sorry

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