Question

Write the equation of the line that passes through (–2, 6) and (2, 14) in slope-intercept form

Answer 1

First, put your points in a coordinate axis

operating
a=8
b=4
the form of your equation is:
\[y=mx+i\]
where
m:slope
i:Intercept
so you need the slope and the intercept
you can find the slope with this expression
\[m=tg \alpha=\frac{ a }{ b }=\frac{ 8 }{ 4 }=2\]
this is the equation of your line
\[y=2x+i\]
and you have two points of this. Replace one of the points in your equation
for (-2,6):
x=-2
y=6
\[6=2(-2)+i\]
\[10=i\]
\[y=2x+10\]

Answer 2

y = 2x + 10 correct answer

Answer 3

y-6 = {(14-6)/[2-(-2)]} x {x-(-2)}
y-6 = 2(x+2)
y = 2x +10 <<y=mx+c form>>