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OpenStudy (anonymous):
I'm really bad at Solving Quadratic Equations w/ 0 as the leading coefficient
OpenStudy (anonymous):
\[x ^{2}-7x=-13 ?\]
OpenStudy (anonymous):
yeah sorry i forgot to include the ^
OpenStudy (anonymous):
\[x ^{2}-7x+13=0\]
you can use the general solution
\[x_{1}= \frac{ -b+\sqrt{b ^{2}-4ac} }{ 2a }\]
\[x_{2}= \frac{ -b-\sqrt{b ^{2}-4ac} }{ 2a }\]
where
a=1
b=-7
c=13
OpenStudy (anonymous):
so basically to solve these types of equations you just substitute and simplify with the quadratic formula?
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OpenStudy (anonymous):
It is the general method for quadratic equations (works for all the quadratic equations ..
but there are some equations where you could do other methods to factoring
OpenStudy (anonymous):
There is another way, which is completing the square, but doing the quadratic formula is fine.
OpenStudy (anonymous):
Thank you soon much!
OpenStudy (anonymous):
soooo*
OpenStudy (anonymous):
jaja, you're welcome :)
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