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Simplify the rational expression. State any restrictions on the variable.
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\[\frac{ k^2-k-2 }{ k^2-4k-5}\]
\[\frac{ (k+1)(k-2) }{ (k+1)(k-5)}\]
\[\frac{ k-2 }{ k-5 }\]
That's the answer but i need to find the other part of the answer
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\[\frac{ (k-2)(k+1) }{(k-5)(k+1)}\] you can eliminate (k+1) but \[k+1\neq0\] \[k\neq-1\] and the same to (k+5) \[k-5\neq0\] \[k\neq5\]
because you can not divide by zero. Is an uncertainty
So it's A?
yes
Thank you so much! :) Gave you a medal!
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