Question

What is the approximate value of 0 , if tan 0 = 7/9 ? ,
38°



52°



74°



16°



63°

Answer 1

@ganeshie8

Answer 2

I need this explained I don't understand this

Answer 3

we can write this:
\[\tan \left( {45} \right) = 1 = \frac{7}{9} + \frac{2}{9} = \tan \theta + \frac{2}{9}\]

Answer 4

so, we have:
\[\tan \theta = \tan \left( {45} \right) - \frac{2}{9}\]
then we can state that \theta is less than 45 degrees

Answer 5

so could I sub one of the answers into the equation lets say Tan(38) what could I sub in for that?

Answer 6

yes! try with 38 degrees

Answer 7

so would 2/9 work still o should I use something different

Answer 8

or*

Answer 9

for current exercise, 2/9 works well, since:
(2/9)+ (7/9)=1= tan(45)

Answer 10

furthermore, since:
\[\tan 30 = \frac{{\sqrt 3 }}{3} > \frac{{1.7}}{3} = \frac{{5.1}}{9}\]
our angle \thta has be greater than 30 degrees

Answer 11

ok

Answer 12

its bigger than 30 and less than 45 so which answer would work

Answer 13

so 38 would be the answer??

Answer 14

yes! That's right!

Answer 15

yes thank you so much

Answer 16

I gave you a medal