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find the solution of the exponential equation 7^(x/2)=5^(1-x)
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\[7^{\frac{ x }{ 2 }}=5^{1-x}\]
\(7^{x/2}=5^{1-x}\) SNAP!!
i am stuck here \[x(\frac{ 1 }{2 }\ln 7+\ln 5)=\ln 5\]
\[x(a)=b\\x=\frac{b}{a}\]
\[x=\frac{ \ln 5 }{ \frac{ 1 }{ 2 }\ln 7+\ln 5 }\]
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for some reason doesn't feel right..
\[\frac{1}{2}\ln7+\ln5=\ln \sqrt{7}+\ln5=\\ln(5\sqrt{7})\\x=\frac{\ln5}{\ln(5\sqrt{7})}\]
i am so stupid -.-.. Thank you!!
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