The Math Club is sponsoring a bake sale. If their goal is to raise at least $200, how many pies must they sell at $4.00 each in order to meet that goal? Write, solve, and graph an inequality that represents this situation.

Question

joel_the_boss · Answer

@ganeshie8 Mind helping me? Trying to refresh on basic algebra before i head into trig. Math has never been my strong point. Thanks. :)

joel_the_boss · Answer

goal is 200-  g 

pies 4.00 each-  4

number of pies sold- n 
$p*n=g$

$4*n=200$
 
$\frac{4}{4}*n= \frac{200}{4}$

$n=50$

is that correct? @vera_ewing @ganeshie8

butterflydreamer · Answer

weeell firstly, you want to note that we're dealing with an inequality :)
"...goal is to raise AT LEAST $200"... so this basically means " $$\ge 200$$
Then we know each pie costs $4
So if n = number of pies and we need to raise at least $200, the inequality should be :
$$4n \ge 200 $$

butterflydreamer · Answer

but yes, you're correct in the way you solved it :) At least 50 pies are needed! 
$$4n \ge 200 \rightarrow n \ge 50 $$

joel_the_boss · Answer

Thank you very much. :) @butterflydreamer

butterflydreamer · Answer

nooo problemo ^_^!