Which of the following statements have the same result? Explain each step in solving each one.
I.f(2) when f(x) = 3x + 2
II.f-1(3) when f(x) = 2 x minus 7, all over 3
III.2y + 14 = 4y - 2
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OpenStudy (freckles):
did you replace x with 2 for I?
OpenStudy (freckles):
in II how you have to do is replace f(x) with 3 and solve for x.
III. you solve for y.
OpenStudy (itsmichelle29):
so I is 8
OpenStudy (itsmichelle29):
@freckles
OpenStudy (itsmichelle29):
and II. i get -1/3 is that correct
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OpenStudy (freckles):
let see 3(2)+2 is 6+2 which is 8 so yes for I
OpenStudy (freckles):
\[3=\frac{2x-7}{3}\]
I think this is what you have above?
OpenStudy (freckles):
and I asked you to replace f(x) with 3 since we want to find f^(-1)(3)
OpenStudy (freckles):
hmm solving that shouldn't give -1/3
OpenStudy (itsmichelle29):
idk what the answer is
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OpenStudy (itsmichelle29):
@freckles
OpenStudy (freckles):
did you try solving the equation I have above?
OpenStudy (freckles):
what is 3(3)?
OpenStudy (freckles):
\[3=\frac{2x-7}{3} \\ 3(3)=2x-7\]
OpenStudy (freckles):
and I will give you another hint
add 7 on both sides
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