Question

WILL FAN & MEDAL
Given: m ∠ EGF= 60° and m∠AGF = 90°; Prove: m ∠ AGB = 30°

Answer 1

Start with what's given
1) m<EGF = 60 -given
2) m<AGF = 90 -given

Answer 2

1) m<EGF = 60 -Given
2) m<AGF = 90 -Given
3) m<BGC = m<EGF -Vertical angles are congruent.
4) m<BGC = 60 -By transitive property of equality.
5) m<AGF + m<AGC = 180 -Linear pair angles are complementary.
6) 90 + m<AGC = 180 -By substitution.
7) m<AGC = 90 -By subtraction property of equality.
8) m<AGB + m<BGC = m<AGC -By angle addition postulate.
9) m<AGB + 60 = 90 -By substitution.
10) m<AGB = 30 -By subtraction property of equality.

Answer 3

i see why it says prove why Agb is 30* because I don't believe its 30*

Answer 4

agb and agf is same length. Thus being as it is they should both be a 90 degree angle.

Answer 5

Yeah 😁 me too but thanks guys