the total value of a collection of dimes and nickels is $2.70. if the total number of coins is 39, how many of each coin is there?
hold on im trying to figure it out
thanks
it is a pain
yeaah lol
\[\large \sf d+n=39 \\\large \sf .1d+.05n=2.7\]
soooo, there is half a nickel??
15 dimes 24 nickels?
thanks man
Woah there, no direct answers. @.Gjallarhorn.
oh ok
lets see.. 15 dimes is 1.50 24 nickels 1.20 addem and you get 2.70
i know im explaining
And the method you used to figure it out?
15 dimes and 24 nickels add up to 39 coins :)
That isn't a method, my friend :)
i just used guess and eliminate
and i got the answer and i explained why that was the answer by adding the values
And that's the problem. We're here to help the asker UNDERSTAND, which your method doesn't do. Your method doesn't work on anything but things like this. With such a small margin of answers, it's easy to guess around and get the answer.
I mean, have you ever had a teacher tell you, "Guess around till you get the answer"? /:
Number of dimes: x Number of nickels: (39-x) 10x + 5(39-x) = 270 (cents makes sense) 5x = 75 x = 15, the number of dimes. 24 Nickels checking.... 10*15+5*24 = 270cents or $2.70 THERE YA GO @bearclaw heres the source http://www.algebra.com/algebra/homework/word/coins/Word_Problems_With_Coins.faq.question.879243.html so your final answer is 15 dimes and 24 nickels, bearclaw. Have a nice day! :)
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