Question

If f(x)=2x^2−4x−3 and g(x)=(x−4)(x+4), find f(x)−g(x).

Answer 1

4x+13

x2−4x+13

3x2−4x+13

−4x2−4x+13

Answer 2

g(x) = x^2 - 16 using identity (a-b)(a+b) = a^2 - b^2

Answer 3

Alright I can help. So Im gonna give you an example

Answer 4

so
f(x) - g(x) =2x^2−4x−3 - (x^2 - 16) = x^2 - 4x + 13

Answer 5

still so confused

Answer 6

please help, i have to finish my class by 9 pm today

Answer 7

f(x) - g(x) = 2x^2−4x−3 - (x^2 - 16)
= 2x^2 - 4x - 3 - x^2 + 16
= 2x^2 - x^2 - 4x - 3 + 16
= x^2 - 4x + 13

is it clear now??

Answer 8

kinda not really

Answer 9

Is this part clear???

g(x) = x^2 - 16 using identity (a-b)(a+b) = a^2 - b^2