Question

factor the polynomial correctly
c^2-64

Answer 1

@Aureyliant

Answer 2

What do you think you should do first?

Answer 3

i really have no clue on this one

Answer 4

Do you know the difference of squares?

Answer 5

i heard of it just forgot what it meant

Answer 6

Trying to factor as a Difference of Squares :

Theory : A difference of two perfect squares, A2 - B2 can be factored into (A+B) • (A-B)

Proof : (A+B) • (A-B) =
A^2 - AB + BA - B^2 =
A^2 - AB + AB - B^2 =
A^2 - B^2

Answer 7

Make sense?

Answer 8

not really

Answer 9

Where?

Answer 10

c^2 is a perfect square
64 is a perfect square

Answer 11

Therefore, we apply the difference of squares.

Answer 12

but how do we factor them

Answer 13

Check : 64 is the square of 8
Check : c2 is the square of c1

Factorization is : (c + 8) • (c - 8)

Answer 14

See? It's simple as that when I apply the difference of squares rules.

Answer 15

so you basically just take the square root of eat number

Answer 16

yes..

Answer 17

refer to one of my first responses for the rules.

Answer 18

so your answer will be c-8

Answer 19

no..

Answer 20

I literally spoonfed you the answer.

Answer 21

A^2 - B^2 can be factored into (A+B) • (A-B)

Answer 22

so... (c-8)(c+8)

Answer 23

Yes.

Answer 24

thank you