Question

Can someone walk me through this problem? I always have a hard time with this.

Answer 1

@EmilyF03 excuse me?

Answer 2

I tried this but it didn't seem to work for me
\[ 8^2=4^2+7^2-2(4)(7)\cos\]

Answer 3

\[ 8^2=4^2+7^2-2(4)(7)\cos(\theta)\]

Answer 4

isolate \(\cos(\theta)\) first

Answer 5

i ended up with -57=cosT but i don't think that's right

Answer 6

you should end up with

-1 = -56cos(T)

right?

Answer 7

dividing -56 both sides gives you

1/56 = cos(T)

Answer 8

don't i need to put it in cos^-1(-56) ?

Answer 9

cos(T) ? shouldn't it be cos(R) since you want to find m < R ?

Answer 10

@jim_thompson5910 ooh oops yepp i was just going off an example in my notes

Answer 11

ah, gotcha