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Simplifying Radicals a^1/2/a^2
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@taramgrant0543664 can you help this also ? LOL
\[\frac{a^n}{a^m}=a^{n-m}\]
You got to it first #unkle lol
, about to post same thing
\[a^{-p}=\frac1{a^p}\]
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what is your final answer @Heartz
hmm
\(\large \cfrac{a^n}{a^m}\implies a^{n-m}\qquad thus\qquad \cfrac{a^{\frac{1}{2}}}{a^2}\implies a^{\frac{1}{2}-2}\implies a^{\square ?}\)
a^3/2
well... notice,the "2" is negative though
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\(\large { \cfrac{a^n}{a^m}\implies a^{n-m}\qquad thus\qquad \cfrac{a^{\frac{1}{2}}}{a^2}\implies a^{\frac{1}{2}-2}\qquad \begin{cases} 2=\cfrac{4}{2} \end{cases}\qquad thus \\ \quad \\ a^{\frac{1}{2}-2}\implies a^{\frac{1}{2}-\frac{4}{2}}\implies a^{\square ?} }\)
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