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Solve the equation the square root of the quantity x plus 4 minus 3 equals 1 for the variable. Show each step of your solution process.
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|dw:1436741205393:dw|
try isolating the square root part by first adding the 3 on both sides
you should then be ready to square both sides in order to cancel out the square root part
\[\left( \sqrt{x+4} \right)^{2}=\left( 4 \right)^{2}\]
so the answer would be x=0?
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@freckles
If you were to do the previous equation, you would get \[x+4=16\]
Then just subtract across and get x and finish with a check.
oh yes i forgot to square it thanks
so x=12
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Yep! And it checks.
thank you @marihelenh
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