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OpenStudy (anonymous):
if 0 is less than or equal to theta less than 360 solve sec^2 (theta)+2sec(2 theta)=0
ANy last min help??? ITs wrong and the answer wasnt -1/2
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OpenStudy (anonymous):
@Loser66
OpenStudy (anonymous):
@Loser66 this is what i got
OpenStudy (anonymous):
@Loser66 Apparently we have to factor this thing out and I don't know how to
OpenStudy (trojanpoem):
significantly , it's typo from him. Check the question the first was also 2theta
OpenStudy (trojanpoem):
Take sec(2theta) as common factor
sec(2theta)(sec(2theta)+2) = 0
either sec(2theta) = 0 or sec(2theta)+2 = 0
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OpenStudy (trojanpoem):
and continue it, don't neglect the restriction "0 is less than or equal to theta less than 360"
OpenStudy (anonymous):
I think I got it! pi/3 and 4pi/3
OpenStudy (trojanpoem):
Loser66, sec(2theta) = 0 is refused.
OpenStudy (trojanpoem):
sec is never equal to 0
OpenStudy (trojanpoem):
Cosine is never undefined so sec 0 is refused
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OpenStudy (trojanpoem):
@Loser66 , You are right.But , The longer the answer is, the higher chance of mistaken. By the way , nice ^^.
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