Question

solve for x: 3|x-3|+2=14

A)No solution
B)x=-1,x=8.3
C)x=0,x=7
D)x=-1,x=7

Answer 1

Add -2 to both sides.
\[\huge~\rm~3(|x−3|)+2+−2=14+−2\]
\[\huge~\rm~3(|x−3|)=12\]
Then we need to divide (both sides)
\[\huge~\rm~\frac{ 3(|x−3|) }{ 3 }=\frac{ 12 }{ 3}\]
We get
\[\huge~\rm~|x-3|=4\]
Solve Absolute Value.
\[\huge~\rm~|x−3|=4\]
We know either :\[\huge~\rm~x−3=4\] \(\huge\color{red}{or}\) \[\huge~\rm~x−3=−4\]

Answer 2

From here just solve for x

Answer 3

so i got x=7 and x=-1

Answer 4

@pooja195

Answer 5

Thats correct! :)
Good job!
welcome to openstudy! :D

Answer 6

Thank you so much for your help :D

Answer 7

No problem! :D