Karen wants to distract her noisy four-year-old child at a restaurant. She pulls out a bag that has 4 black marbles, 8 red marbles, and 9 green marbles. The child likes green marbles. What is the probability Karen will randomly pick a green marble from the bag in one try?

Question

mehek14 · Answer

green marble = 9
total # of marbles = 21

set up a fraction
$\dfrac{9}{21}$
divide by 3
$\dfrac{3}{7}$

wil476003 · Answer

43 percent or 9/21 3/7

anonymous · Answer

Total no.of marbles = (4+8+9) = 21
No.of green marbles = 9
therefore, P(green) = 9/21
dividing above and below by 3 we get: 3/7

anonymous · Answer

thx