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How can1/3 x − 2 = 1/4 x + 11 be set up as a system of equations?
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use a second variable, y y = 1/3x - 2 y = 1/4x + 11
3y − x = −6 4y − x = 44 3y + x = −6 4y + x = 44 3y − 3x = −6 4y − 4x = 44 3y + 3x = −6 4y + 4x = 44
those are the answers
@Vocaloid
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well, we can start off with y = 1/3x - 2 y = 1/4x + 11 we can multiply the first equation by 3, and the second equation by 4, giving us 3y = x - 6 4y = x + 44 we can then subtract x from both sides, giving us 3y − x = −6 4y − x = 44
Thanks :)
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