Which of the following ordered pairs represents the solution to the system given below? 2x + y = 20 4x − 2y = 40 (10, 0) (0, 10) (4, 2) (10, −10)
You can use substitution to solve.
\(\sf 4x - 2y = 40\) Subtract 4x to both sides: \(\sf -2y = -4x + 40\) Divide -2 to both sides: \(\sf y = 2x - 20\) Now plug in \(\sf 2x - 20\) into the first equation for \(\sf y\) and solve for \(\sf x\), then plug that into any of the two equations to find \(\sf y\).
Can you do that?
I'd rather have you walk me through it can you?
Okay, we have: \(\sf 2x + (2x - 20) = 20\) Can you solve that for \(\sf x\)?
10
So it's 10, ?
continuing from here, we know that x = 10 since you just solved for it let's take one of our original equations 2x + y = 20 let x = 10 and solve for y
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