Question

I need help with this question,

The graph below shows the value of Edna's profits f(t), in dollars, after t months:

graph of quadratic function f of t having x intercepts at 6, 0 and 18, 0, vertex at 12, negative 36, and passes through point 21, 41.25

What is the closest approximate average rate of change for Edna's profits from the 18th month to the 21st month?

Answer 1

whees the graph??

Answer 2

I don't know how to put it on here but the part that says graph of quadratic function f of x that is what is on the graph.

Answer 3

click on attach file i can't understand u

Answer 4

Oh ok sorry on my computer the screen is small so i didn't see that okay one sec and i will put the graph.

Answer 5

ok :3

Answer 6

Here is the graph

Answer 7

ok wait up

Answer 8

ok

Answer 9

rate of change= slope

Answer 10

do you know how to find the slope?

Answer 11

since you are not answering i will show ya

Answer 12

slope=\[\frac{ y2-y1 }{ x2-x1 }\]

Answer 13

so your two points from 18 months to 21 months is: (0,18) and (21,41.25).

Answer 14

Hey sorry it wouldn't let me type lol

Answer 15

plug the points into the slope formula and you get:\[\frac{ 41.25-18 }{ 21-0 } =\frac{ 23.25 }{ 21 }\]

Answer 16

thats the rate o change :3

Answer 17

g'night btw

Answer 18

Oh okay thank you! Lol

Answer 19

:)