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OpenStudy (anonymous):
What is the axis of symmetry for y = {x^2} - 8x + 8? Be sure to use correct notation.
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OpenStudy (alekos):
axis of symmetry, x = -b/2a
OpenStudy (alekos):
where the general form of a parabola is y= ax^2+bx+c
OpenStudy (anonymous):
Okay I know the vertex is 4,-8
OpenStudy (alekos):
well then the axis of symmetry is just the x value of the vertex
OpenStudy (anonymous):
which is 4 my other problem was setting it up as an equation
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OpenStudy (anonymous):
y = (x-4)^2 - 8 this is what i have
OpenStudy (alekos):
yeah thats correct
OpenStudy (anonymous):
though it says I was wrong when I tried to submit it
OpenStudy (alekos):
who says it was wrong?
OpenStudy (anonymous):
when I try to submit my assignment it counts the equation wrong
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OpenStudy (alekos):
But that is the correct vertex form of your original equation
and x=4 is the equation for the axis of symmetry
OpenStudy (anonymous):
that's what happen I have -4
OpenStudy (alekos):
ok, there you go
OpenStudy (anonymous):
so its x=4
OpenStudy (alekos):
oh yes it is
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OpenStudy (anonymous):
it's right thank you :D
OpenStudy (alekos):
no problemo
OpenStudy (anonymous):
although I have more questions I may need help on in a few minutes
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