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Physics
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OpenStudy (yumyum247):
help!!!!
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OpenStudy (yumyum247):
OpenStudy (yumyum247):
@gleem
OpenStudy (yumyum247):
can you please check my work????????
OpenStudy (yumyum247):
@dan815 can you please check my work????
OpenStudy (anonymous):
looks good until the last step. I think you miscopied a previous result.
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OpenStudy (yumyum247):
please help me what did i do wrong????
OpenStudy (yumyum247):
@Michele_Laino
OpenStudy (yumyum247):
@IrishBoy123 help please!!!
OpenStudy (yumyum247):
@welshfella
OpenStudy (yumyum247):
@shamim
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OpenStudy (yumyum247):
@Jaynator495
OpenStudy (anonymous):
0.342m/4 = 0.0855 m
OpenStudy (yumyum247):
ok i didn't know about this equation, what is it used for???? f1=v4L
OpenStudy (yumyum247):
can you please list all the formulas necessary related to this unit.
OpenStudy (irishboy123):
the closed pipe [closed at one end] has a constraint at the closed end, which must be a node. the fundamental resonance occurs when \(\lambda = 4L\)
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OpenStudy (irishboy123):
as \(v = f.\lambda\), then \(\lambda_1 = \frac{v}{f}\) and \(L_1 = \frac{v}{4*f}\)
OpenStudy (yumyum247):
can you please tell me how a fundamental resonance occur when λ=4L with a quick sketch!!!
OpenStudy (irishboy123):
|dw:1436898866645:dw|
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