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Mathematics 15 Online
OpenStudy (anonymous):

I'll FAN & MEDAL!!! Help me please Find the sum.

OpenStudy (anonymous):

OpenStudy (freckles):

you can multiply first fraction by a/a and multiply second fraction by b/b and that way you will have the same denominator

OpenStudy (freckles):

then you will be able to combine the fractions

OpenStudy (anonymous):

i know the common denominator is abc

OpenStudy (anonymous):

im confused about how to find the numerator

OpenStudy (freckles):

well did you multiply the fractions by what I have asked you to? and if so what do you have so far?

OpenStudy (anonymous):

|dw:1436972905311:dw|

OpenStudy (freckles):

\[\frac{3a}{bc} \cdot \frac{a}{a}=\frac{3a(a)}{bc(a)}=\frac{?}{abc} \\ \frac{2b}{ac} \cdot \frac{b}{b} =\frac{2b(b)}{ac(b)}=\frac{?}{abc}\] but you should have a plus between the two numerator terms

OpenStudy (freckles):

and yes 3a(a)=3a^2 and yes 2b(b)=2b^2 \[\frac{3a}{bc}+\frac{2b}{ac} \\ \frac{3a(a)}{bc(a)}+\frac{2b(b)}{ac(b)} \\ \frac{3a^2}{abc}+\frac{2b^2}{abc} \\ \frac{3a^2+2b^2}{abc}\]

OpenStudy (anonymous):

oh sorry i forgot to put it there

OpenStudy (freckles):

but that is all you cannot go any further you are done

OpenStudy (anonymous):

Thank you soo much:)

OpenStudy (freckles):

np

OpenStudy (freckles):

I will give you a medal because you did awesome.

OpenStudy (anonymous):

aww thank you :)

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