Question

Help

Answer 1

How can you solve this algebraically ln(x2-x) =ln 6

Answer 2

well both arguments should be the same, just equal both and solve the equation

Answer 3

x^2-x = 6

i know the answer is 3 but don't know how to express it algebraically

Answer 4

Hint: \[\huge e^{lnx} = x\]

Answer 5

Well I'm using the one to one property of exponents but don't know how i can algebraically express how to solve it??

Answer 6

x^2 -x =6

Answer 7

That's it now just factor

Answer 8

No, remember how you factor, what two numbers add up to -1 and multiply to give -6, those are your two factors.

Answer 9

(x-3) (x+2)

Answer 10

x=3 x=-2

Answer 11

There we go, so our roots are x = 3, and x = -2 :)

Answer 12

Thanks!
but we omit -2 because the natural logs domain is from (0,oo) right?

Answer 13

Yes :)