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How many solutions does the equation −3y + 3y + 4 = 4 have?
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what do you think?
try plugging in y = 1,2 and 3 and see what you get
infinitly many
@welshfella
right
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The work of a student to solve the equation 3(3y − 8) = 10 + 3y is shown below: Step 1: 3(3y − 8) = 10 + 3y Step 2: 6y − 5 = 10 + 3y Step 3: 3y − 5 = 10 Step 4: 3y = 15 Step 5: y = 5 In which step did the student first make an error and what is the correct step?
can you help me with one more?
any real number can be substituted for y and the equation will still hold
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