Question

Can someone help me with this? (Picture below)

Answer 1

Are you allowed imaginary numbers?

Answer 2

Also, what do you think is the correct answer?

Answer 3

Well, what do you think is the correct answer?

Answer 4

@Nixy I believe it is the first one.

Answer 5

It is the second one.

Answer 6

The reason why it is the second one is because if you put -5 in
\( \huge \sqrt{x-2} \)

\( \huge \sqrt{-5-2} \) we get \( \huge \sqrt{-5-2} = i\sqrt{7} \) which is an imaginary number and not a real number

Answer 7

@Nixy thank you.

Answer 8

YW