Question

Given the parent functions f(x) = 3x + 2 and g(x) = 5x − 10, what is g(x) − f(x)?

g(x) − f(x) = 5x − 8 − 3x
g(x) − f(x) = 5x − 12 − 3x
g(x) − f(x) = 3x − 8 − 5x
g(x) − f(x) = 3x + 12 − 5x

Answer 1

\[\Large \color{red}{f(x) = 3x+2}\]
\[\Large \color{blue}{g(x) = 5x-10}\]
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\[\Large \color{blue}{g(x)}-\color{red}{f(x)}=\color{blue}{(5x-10)}-\color{red}{(3x+2)}\]
I'll let you finish

Answer 2

What next

Answer 3

@jim_thompson5910

Answer 4

i get =2x−12

Answer 5

and that not the answer

Answer 6

look through the choices and see which ones have a "-12" in it

for some reason, they didn't combine the x terms, idk why

Answer 7

g(x) = 5^x − 10,

Answer 8

oh these are exponentials?

Answer 9

5 is to the power of x sorry

Answer 10

I see now

Answer 11

3 is not only 5

Answer 12

you cannot do \[\Large 5^x - 3^x = 2^x\]

Answer 13

\[\Large a^x - b^x \ne (a-b)^x\]

Answer 14

so whats the answer

Answer 15

you tell me

Answer 16

B i think or A

Answer 17

what's your reasoning on each?

Answer 18

B for -12 or A for -10+2

Answer 19

but you have to distribute the negative through

Answer 20

\[\Large \color{red}{f(x) = 3^x+2}\]
\[\Large \color{blue}{g(x) = 5^x-10}\]
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\[\Large \color{blue}{g(x)}-\color{red}{f(x)}=\color{blue}{(5^x-10)}-\color{red}{(3^x+2)}\]
\[\Large g(x) - f(x) = 5^x - 10 - 3^x - 2\]
\[\Large g(x) - f(x) = 5^x - 12 - 3^x\]

Answer 21

notice how \(\Large -( 3^x + 2)\) becomes \(\Large - 3^x - 2\)

Answer 22

Oh okayyyy can u help me with one more

Answer 23

ok one more

Answer 24

Given the parent functions f(x) = log10 x and g(x) = 3x − 1, what is f(x) • g(x)?

f(x) • g(x) = log10 (3x − 1)x
f(x) • g(x) = log10 x3x − 1
f(x) • g(x) = 3x log10 x + log10 x
f(x) • g(x) = log10 x − 3x log10 x

Answer 25

i think its A

Answer 26

@jim_thompson5910

Answer 27

can you post a screenshot of this?

Answer 28

yeah

Answer 29

@jim_thompson5910

Answer 30

none of the answer choices are correct. There's one that's close, but it's off by a negative sign

Answer 31

there has to be a typo somewhere

Answer 32

oh nvm I see the answer

Answer 33

pkay thanks anyways

Answer 34

hint: y*log(x) = log(x^y)

Answer 35

if fine i turned the tyest in

Answer 36

thanks