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Mathematics 14 Online
OpenStudy (anonymous):

HELP PLZ WILL MEDAL AND FAN A firecracker has dimensions as shown. Height is 14 cm, radius is 1 cm and slant height of the cone is 2 cm. Paper covers the entire surface area including the cone, the lateral area and the bottom circle but does not include the tail. What is the best approximate area of paper needed to wrap the firecracker? (Use three point one four for pi. Round your answer to the nearest whole number.)

OpenStudy (mertsj):

Find the surface area of the cylindrical part first: Surface Area = 2 pi r h

OpenStudy (triciaal):

my approach would be to find the base area of the cylinder add the surface area of the cylinder add the surface area of the cone

OpenStudy (mertsj):

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OpenStudy (anonymous):

SO I DO 2X14X3.14

OpenStudy (mertsj):

yes

OpenStudy (anonymous):

okay that got 87.92

OpenStudy (mertsj):

Then find the area of the conical part. The formula is Surface Area = pi r L where L is the slant height.

OpenStudy (mertsj):

Then add the two answers together.

OpenStudy (anonymous):

can you draw a picture please

OpenStudy (mertsj):

|dw:1437187206716:dw|

OpenStudy (anonymous):

6.28

OpenStudy (anonymous):

94.2 is my answer

OpenStudy (triciaal):

|dw:1437192121647:dw|

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