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Verify the identity. Cot[theta - pi/2] = -tan theta
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\[Cot \left( \theta - \frac{ \pi }{ 2 } \right) = -\tan \theta\]
@oleg3321
I have to verify the identity and show my work
we know that cot(-theta) = -cot(theta) we also know that cot(pi/2-theta) = tan(theta) multiply both sides by -1 we get -- -cot(pi/2-theta)=-tan(theta) we can write -cot(pi/2-theta) as cot(theta-pi/2) so nw we hav cot(theta-pi/2)= -tan(theta)
ok so where do i go from there? Im literally lost and I need to show my work
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Or is that the answer? @imqwerty
Anyone?
wait :)
ok lol sorry
don't get lost :) that is the answer @EllenJaz17
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oh ok, lol thank you!
ur welcome :) @EllenJaz17
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