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what is the equation of a line passing through -3,7 and having a slope of -1/5
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in slope intercept form?
yes
\[\huge~\rm~y-y_1=m(x-x_1)\] m=slope x1=x coordinate y1=y coordinate
-3=x1 7=y1 -1/5=m plug them in
options y=-5x+22 y=5x+22 y=-1/5x+32/5 y=-1/5x+32/5 y=-1/5x+22
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Ye we'll get to that
\[\huge~\rm~y-7=-1/5(x-(-3))\] -3=x1 7=y1 -1/5=m \[\huge~\rm~y-7=-1/5(x+3)\] can you isolate y from here?
start by distributing −1/5(x+3)
I don't know how to do that?
-1/5x+ -1/5(3)
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-1/5x+-0.6
help
what is the question @Kaelyn78
nevermind I worked through it, thank you anyway
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