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Gabriel is using logarithms to solve the equation 52x = 27. Which of the following equations would be equivalent to his original expression? 5 log 2x = log 27 2 log 5 = x log 27 x log 5 = 2 log 27 2x log 5 = log 27
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52\(^x\)=27 , like this, right?
no
5^2x=27
5\(^{2x}\)=27 ?
take log of both sides.
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and then apply the rule: log(c\(^w\))=w log(c)
5\(^{2x}\)=27 when you take the log of both sides, you get: log(5\(^{2x}\))=log(27) then apply the rule that I posted right before this, and you get?
i think
yes, that is right!
thank u
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Alright!, Yw!
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