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Mathematics 21 Online
OpenStudy (itsmichelle29):

Gabriel is using logarithms to solve the equation 52x = 27. Which of the following equations would be equivalent to his original expression? 5 log 2x = log 27 2 log 5 = x log 27 x log 5 = 2 log 27 2x log 5 = log 27

OpenStudy (solomonzelman):

52\(^x\)=27 , like this, right?

OpenStudy (itsmichelle29):

no

OpenStudy (itsmichelle29):

5^2x=27

OpenStudy (solomonzelman):

5\(^{2x}\)=27 ?

OpenStudy (solomonzelman):

take log of both sides.

OpenStudy (solomonzelman):

and then apply the rule: log(c\(^w\))=w log(c)

OpenStudy (solomonzelman):

5\(^{2x}\)=27 when you take the log of both sides, you get: log(5\(^{2x}\))=log(27) then apply the rule that I posted right before this, and you get?

OpenStudy (itsmichelle29):

i think

OpenStudy (solomonzelman):

yes, that is right!

OpenStudy (itsmichelle29):

thank u

OpenStudy (solomonzelman):

Alright!, Yw!

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